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How do you use the method of cylindrical shells to find the volume of the solid obtained by rotating the region bounded by $y = 32 - x^{2}$ $y = 32 - x^2$ and $y = x^{2}$ $y= x^2$ revolved about the x=4?

1 Answer

Jan 12, 2017

0

Explanation:

since $y = 32 - x^{2} and y = x^{2}$ $y=32-x^2 and y=x^2$ meet at $x = 4$ $x=4$ so there no solid exist when rotated at x=4.

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