Question

How do you use the point (6,-11) on the terminal side of the angle to evaluate the six trigonometric functions?

Answer 1

see below

Explanation:

Since every ordered pair in the unit circle has coordinates `(costheta,sintheta)` then the point `(6,-11)` is in quadrant IV
and hence,
`cos theta=6, sin theta=-11, tan theta=sin theta/cos theta =-11/6,`

`sec theta=1/cos theta =1/6, csc theta=1/sin theta=1/-11`

`cot theta=costheta/sin theta=6/-11`