Question

How do you use the product rule to differentiate `g(s)=sqrts(4-s^2)`?

Answer 1

`g'(s)=(4-5s^2)/(2sqrts)`

Explanation:

`g'(s)=1/(2sqrts)* (4 - s^2)+sqrts*(-2s)`

`=(4-s^2)/(2sqrts)-2ssqrts`

`(4-s^2-2ssqrts*(2sqrts))/(2sqrts)`

`(4-s^2-4s^2)/(2sqrts)`

`(4-5s^2)/(2sqrts)`