How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer AJ Speller Sep 23, 2014 Quotient Rule: #y'=(g(x)f'(x)-f(x)g'(x))/(g(x))^2# #y=f(x)/g(x)=(2x^4-3x)/(4x-1)# #f'(x)=8x^3-3# #g'(x)=4# #(g(x))^2=(4x-1)^2# #y'=((4x-1)(8x^3-3)-(2x^4-3x)(4))/(4x-1)^2# #y'=(32x^4-12x-8x^3+3-8x^4+12x)/(4x-1)^2# Simplify for combining like terms. #Solution->y'=(24x^4-8x^3+3)/(4x-1)^2# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? How do you use the quotient rule to find the derivative of #y=(1-x*e^x)/(x+e^x)# ? See all questions in Quotient Rule Impact of this question 15595 views around the world You can reuse this answer Creative Commons License