How do you use the remainder theorem to determine the remainder when $3t^ 2 + 5t – 7$ is divided by t – 5?

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Answer 1 · 2016-08-07T17:36:33

$93$ .

As per the Remainder Theorem , if a Polynomial $P(t)$ is divided

by $(t-a)$ , the Remainder is $P(a)$ .

Hence, we have, the remainder $P(5)=3(5)^2+5(5)-7=93$ .

Otherwise, let us observe that,

$P(t)=3t^2+5t-7=3t^2-15t+20t-100+93$

$=3t(t-5)+20(t-5)+93=(t-5)(3t+20)+93$ , so the

remainder, after division of $P(t)$ by $(t-5)$ will be $93$ , as before!

Enjoy Maths.!

How do you use the remainder theorem to determine the remainder when 3t^ 2 + 5t – 73t^ 2 + 5t – 7 is divided by t – 5?