How do you use the second derivative test to find the local extrema for #f(x)=e^(x^2)#?
1 Answer
Apr 4, 2018
The function
Explanation:
Evaluate the first and second derivatives of the function:
Solving the equation:
as the exponential is never null we can see that the only critical point for the function is
Then we see that;
so that the critical point is a local minimum.
graph{e^(x^2) [-2, 2, -1, 10]}