How do you use the substitution method to solve $y = 6 x + 5, 6 x - y = 7$ $y=6x+5, 6x-y=7$ ?

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Answer 1 · 2017-01-05T14:45:57

This system has no solutions. See explanation.

The variable $y$ $y$ is calculated in the first equation, so we can substitute it to the second:

$6 x - (6 x + 5) = 7$ $6x-(6x+5)=7$

$6 x - 6 x - 5 = 7$ $6x-6x-5=7$

$- 5 = 7$ $-5=7$

This equation is false, so the starting system has no solutions.

How do you use the substitution method to solve y=6x+5,6x−y=7y=6x+5, 6x-y=7?