How do you use the sum and difference formula to simplify #(1-tan40tan20)/(tan40+tan20)#?
1 Answer
Explanation:
The basic sum and difference formulae for
#sin(alpha + beta) = sin alpha cos beta + sin beta cos alpha#
#sin(alpha - beta) = sin alpha cos beta - sin beta cos alpha#
#cos(alpha + beta) = cos alpha cos beta - sin alpha sin beta#
#cos(alpha - beta) = cos alpha cos beta + sin alpha sin beta#
There are also sum and difference formulae for
#tan(alpha+beta) = sin(alpha+beta)/cos(alpha+beta)#
#color(white)(tan(alpha+beta)) = (sin alpha cos beta + sin beta cos alpha)/(cos alpha cos beta - sin alpha sin beta)#
#color(white)(tan(alpha+beta)) = ((sin alpha cos beta + sin beta cos alpha) -: (cos alpha cos beta))/((cos alpha cos beta - sin alpha sin beta) -: (cos alpha cos beta))#
#color(white)(tan(alpha+beta)) = (tan alpha + tan beta)/(1 - tan alpha tan beta)#
Similarly:
#tan(alpha-beta) = (tan alpha - tan beta)/(1 + tan alpha tan beta)#
So notice that:
#(1 - tan 40 tan 20) / (tan 40 + tan 20) = 1/(tan (40+20)) = 1/tan 60 = cot 60#