Question

How do you verify `[(cosx - 1)^2] / [sin^2 x] = [1 - cos x] / [1 + cos x]`?

Answer 1

LHS= `(cos x-1)^2 /sin^2 x = (1-cos x)^2 / (1-cos^2 x)`

= `(1-cos x)^2 / ((1-cos x)(1+cos x))`

=`(1-cos x)/ (1+cos x)`= RHS