How do you verify #sintheta+costheta=(2sin^2theta-1)/(sintheta-costheta)#?

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Answer 1 · 2016-11-12T09:35:14

see below

#sin theta +cos theta=(2sin^2theta-1)/(sin theta-costheta)#

Left Side:#=sin theta +cos theta#

#=(sin theta +cos theta)/1*(sintheta-costheta)/(sintheta-costheta)#

#=(sin^2theta-cos^2theta)/(sin theta -cos theta)#

#=(sin^2theta-(1-sin^2theta))/(sin theta -cos theta)#

#=(sin^2theta-1+sin^2theta)/(sin theta -cos theta)#

#=(sin^2theta+sin^2theta-1)/(sin theta -cos theta)#

#=(2sin^2theta-1)/(sin theta -cos theta)#

#:.=#Right Side