How do you verify # tan^2(a) - sin^2(a)=tan^2(a)sin^2(a)#?

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Answer 1 · 2016-04-17T02:36:40

See below

Left Side #=sin^2a/cos^2a - sin^2a#

#=(sin^2a-sin^2acos^2a)/cos^2a#

#=(sin ^2a(1-cos^2a))/cos ^2a#

#=(sin ^2a xx sin^2a)/cos^2a#

#=sin^2a/cos^2a xx sin^2a#

#=tan^2a sin^2a#

#=#Right side