How do you verify #tan(theta)/cot(theta)=tan^2(theta)#? Trigonometry Trigonometric Identities and Equations Proving Identities 1 Answer Alan P. Nov 15, 2015 Use the definition of #cot(theta)# as the inverse of #tan(theta)# and the fact that dividing by #1/x# is the same as multiplying by #x# Explanation: #(tan(theta))/(cot(theta))# #color(white)("XXX")=tan(theta) div cot(theta)# #color(white)("XXX")=tan(theta) div 1/(tan(theta)) # [by definition of #cot(theta)#] #color(white)("XXX")=tan(theta)xxtan(theta) # [since #axx1/x <=> axxx#] #color(white)("XXX")=tan^2(theta)# Answer link Related questions What does it mean to prove a trigonometric identity? How do you prove #\csc \theta \times \tan \theta = \sec \theta#? How do you prove #(1-\cos^2 x)(1+\cot^2 x) = 1#? How do you show that #2 \sin x \cos x = \sin 2x#? is true for #(5pi)/6#? How do you prove that #sec xcot x = csc x#? How do you prove that #cos 2x(1 + tan 2x) = 1#? How do you prove that #(2sinx)/[secx(cos4x-sin4x)]=tan2x#? How do you verify the identity: #-cotx =(sin3x+sinx)/(cos3x-cosx)#? How do you prove that #(tanx+cosx)/(1+sinx)=secx#? How do you prove the identity #(sinx - cosx)/(sinx + cosx) = (2sin^2x-1)/(1+2sinxcosx)#? See all questions in Proving Identities Impact of this question 2329 views around the world You can reuse this answer Creative Commons License