How do you verify the identity #sin(A+pi)=-sinA#?

1 Answer
May 18, 2018

There are multiple ways of proving the identity. Please, see below.

Explanation:

First way, probably the more direct method, is by the unit circle:

Poorly created image by me in Paint.

We see that, if we add #pi# to some angle #theta#, or in our case, #A#, #|sin theta| = |sin (theta+pi)|#, but since thery're on opposite parts of the center #O#, which is not in the image, they're of opposite sign.

#color(red)( :. sin(A+pi) = - sinA#

Another method to verify our relation is by applying the sum formula for sine:

#sin(a+b) = sinacosb+cosasinb#

#=> sin(A+pi) = sinAcospi + cosAsinpi=-sinA#

#color(red)( :. sin(A+pi)=-sinA#