How do you verify the identity sin(A+pi)=-sinAsin(A+π)=sinA?

1 Answer
May 18, 2018

There are multiple ways of proving the identity. Please, see below.

Explanation:

First way, probably the more direct method, is by the unit circle:

Poorly created image by me in Paint.

We see that, if we add piπ to some angle thetaθ, or in our case, AA, |sin theta| = |sin (theta+pi)||sinθ|=|sin(θ+π)|, but since thery're on opposite parts of the center OO, which is not in the image, they're of opposite sign.

color(red)( :. sin(A+pi) = - sinA

Another method to verify our relation is by applying the sum formula for sine:

sin(a+b) = sinacosb+cosasinb

=> sin(A+pi) = sinAcospi + cosAsinpi=-sinA

color(red)( :. sin(A+pi)=-sinA