How do you write #0.386# in scientific notation?

2 Answers
Jun 9, 2016

In scientific notation #0.386=3.86xx10^(-1)#

Explanation:

In scientific notation, we write a number so that it has single digit to the left of decimal sign and is multiplied by an integer power of #10#.

Note that moving decimal #p# digits to right is equivalent to multiplying by #10^p# and moving decimal #q# digits to left is equivalent to dividing by #10^q#.

Hence, we should either divide the number by #10^p# i.e. multiply by #10^(-p)# (if moving decimal to right) or multiply the number by #10^q# (if moving decimal to left).

In other words, it is written as #axx10^n#, where #1<=a<10# and #n# is an integer.

To write #0,386# in scientific notation, we will have to move the decimal point one point to right, which literally means multiplying by #10#.

Hence in scientific notation #0.386=3.86xx10^(-1)# (note that as we have moved decimal one point to right we are multiplying by #10^(-1)#.

Jun 9, 2016

#3.86xx10^(-1)#

Explanation:

Given:#" "0.386#

#color(blue)("Point 1")#
Objective is to have just one none zero digit to the left of the decimal and everything else on the other side.

'........................................................................
#color(blue)("Point 2")#
If you multiply a value by 1 you do not change its 'intrinsic' value. However, 1 comes in many forms. For example:

#" "2/2"; "4/4"; "sqrt(7)/sqrt(7)"; "(-1)/(-1)"; "10/10#

So we can multiply by 1 and not change the intrinsic value but we can change the way it looks.
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Answering your question")#

Multiply by 1 but in the form of #1=10/10# giving:

#0.386xx10/10#

This is the same as: #(0.386xx10)xx1/10#

Which is the same as: #(3.86)xx1/10" "larr" nearly there!"#

Another way of writing #xx1/10" is " xx10^(-1)#

So #3.86xx1/10" "->" "3.86xx10^(-1)#

So #0.386" is the same as "3.86xx10^(-1)#