How do you write #225^(-1/2)=1/15# in Log form? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer Shwetank Mauria Sep 19, 2016 #225^(-1/2)=1/15# is written as #log_225 (1/15)=-1/2# in log form. Explanation: #a^m=b# is written as #log_a b=m# in log form. Hence #225^(-1/2)=1/15# is written as #log_225 (1/15)=-1/2# in log form. Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 1909 views around the world You can reuse this answer Creative Commons License