How do you write #2sin2cos2# as a single trigonometric function?
1 Answer
Jul 2, 2016
sin 4
Explanation:
Apply the trig identity:
sin 2a = 2sin a.cos a
2sin 2cos 2 = sin 4
sin 4
Apply the trig identity:
sin 2a = 2sin a.cos a
2sin 2cos 2 = sin 4