How do you write $2x - 5y = 10$ in slope intercept form?

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Answer 1 · 2016-12-21T17:01:08

$y=-2+2/5x$

Given -

$2x-5y=10$

Solve it for $y$
Add $-2x$ to both sides

$2x-2x-5y=10-2x$
$cancel(2x)cancel(-2x)-5y=10-2x$

Divide both sides by $-5$

$(-5y)/(-5)=(10-2x)/(-5)$

$(cancel(-5)y)/cancel(-5)=(10-2x)/(-5)$
$y=(10-2x)/(-5)$
$y=10/(-5)-(2x)/(-5)$
$y=-2+2/5x$

How do you write 2x - 5y = 102x - 5y = 10 in slope intercept form?