Question

How do you write `3log_(4)16=2` in exponential form?

Answer 1

`4^2=16`

Explanation:

According to the definition of log:
`y=log_bx` is equivalent to `b^y=x`

So we have:
`3log_(4)(16)=2`
`log_(4)(16^3)=2`

Compare what we have to the definition of log:
`y=2`
`b=4`
`x=16^3`

Therefore:
`4^2=16^3`

However, `4^2` is definitely not equal to `16^3`. I think you probably meant "`log_4(16)=2`" instead, which would have resulted to the answer `color(blue)(4^2=16)`.