How do you write $3x - 2y = 12$ into slope intercept form?

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Answer 1 · 2015-08-09T21:15:26

Isolate $y$ :

You can isolate $y$ to get to the form:
$y=mx+c$ as:
$y=3/2x-12/2$
$y=3/2x-6$
Where:
Slope $m=3/2$
Intercept $c=-6$

How do you write 3x - 2y = 123x - 2y = 12 into slope intercept form?