How do you write $3x - 2y= 5$ into slope intercept form?

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Answer 1 · 2015-08-22T19:22:43

$y = 3/2x - 5/2$

For a general line $y$ , the equation of the line in slope-intercept form looks like this

$color(blue)(y = mx + b)" "$ , where

$m$ - the slope of the line;
$b$ - the $y$ -intercept.

So basically, all you have to do to write the equation for your line in sloper-intercept form is isolate $y$ on one side of the equation.

Start by adding $-3x$ to both sides to get

$-color(red)(cancel(color(black)(3x))) + color(red)(cancel(color(black)(3x))) - 2y = 5 - 3x$

$-2y = -3x + 5$

Now divide both sides of the equation by $-2$ to get

$(color(red)(cancel(color(black)(-2))) * y)/color(red)(cancel(color(black)(-2))) = ((-3))/((-2))x + 5/((-2))$

$color(green)(y = 3/2x - 5/2)$

How do you write 3x - 2y= 5 3x - 2y= 5 into slope intercept form?