How do you write $3 x - 4 y - 16 = 0$ $3x-4y-16=0$ into slope intercept form?

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How do you write $3 x - 4 y - 16 = 0$ $3x-4y-16=0$ into slope intercept form?

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Answer 1 · 2015-08-14T18:38:41

I found: $y = \frac{3}{4} x - 4$ $y=3/4x-4$

Explanation:

The Slope-Intercept form in general is:
$y = m x + c$ $y=mx+c$
where:
$m =$ $m=$ slope;
$c =$ $c=$ intercept.
You need to isolate $y$ $y$ and you have:
$- 4 y = - 3 x + 16$ $-4y=-3x+16$
and:
$y = \frac{3}{4} x - 4$ $y=3/4x-4$
so:
Slope $= m = \frac{3}{4}$ $=m=3/4$
Intercept $= c = - 4$ $=c=-4$

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How do you write $3 x - 4 y - 16 = 0$ $3x-4y-16=0$ into slope intercept form?

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How do you write $3 x - 4 y - 16 = 0$ $3x-4y-16=0$ into slope intercept form?