How do you write #3x+9=7/2y# in standard form?

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Answer 1 · 2018-07-24T19:39:16

#6x - 7y = -18#

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Let's make it in this form.

First, subtract #color(blue)(7/2)# from both sides:
#3x -7/2y + 9 = 0#

Subtract #color(blue)9# from both sides:
#3x - 7/2y = -9#

In standard form, all the terms also have to be integers #(-3, -2, -1, 0, 1, 2, 3...)#

So multiply both sides by #2#:
#2 * (3x - 7/2y) = -9 * 2#

#6x - 7y = -18#

This is now in standard linear form, #Ax + By = C#.

Hope this helps!