How do you write $3 x + 9 = \frac{7}{2} y$ $3x+9=7/2y$ in standard form?

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Answer 1 · 2018-07-24T19:39:16

$6 x - 7 y = - 18$ $6x - 7y = -18$

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Let's make it in this form.

First, subtract $\frac{7}{2}$ $color(blue)(7/2)$ from both sides:
$3 x - \frac{7}{2} y + 9 = 0$ $3x -7/2y + 9 = 0$

Subtract $9$ $color(blue)9$ from both sides:
$3 x - \frac{7}{2} y = - 9$ $3x - 7/2y = -9$

In standard form, all the terms also have to be integers $(-3, -2, -1, 0, 1, 2, 3...)$

So multiply both sides by $2$ :
$2 * (3x - 7/2y) = -9 * 2$

$6x - 7y = -18$

This is now in standard linear form, $Ax + By = C$ .

Hope this helps!

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