How do you write #5x-y=1/4# in slope intercept form?

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Answer 1 · 2016-11-24T05:51:55

Solve the equation for #y#.

Solve for #y#.

5x-y=1/4#

Subtract #5x# from both sides.

#-y=-5x+1/4#

Divide both sides by #-1#.

#y=5x-1/4#

This equation is in the slope-intercept form, #y=mx+b#, where the slope, #m# is #5#, and the y-intercept, #b# is #-1/4#.

graph{y=5x-1/4 [-10, 10, -5, 5]}