How do you write #6g^-5# using only positive exponents?

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Answer 1 · 2016-10-01T07:22:52

#= 6/x^5#

Recall: one of the indices laws: #x^-m = 1/x^m#

In #6g^-5#, note that it is only #g# that has the index of -5.

#6g^-5 = 6 xx g^-5#

#= 6/x^5#

If it had been #" "(6g)^-5#

then it means that both 6 and #g# have the index -5.

#(6g)^-5 = 1/((6g)^5)#

Be sure to look at the details carefully in Algebra.