How do you write $7^{- 6} = y$ $7^-6=y$ in logarithmic form?

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Answer 1 · 2016-10-27T19:02:41

${log}_{7} y = - 6$ $log_7 y = -6$

$7^{- 6} = y$ $7^-6 = y$ -> Use the definition ${log}_{b} x = y \Leftrightarrow b^{y} = x$ $log_bx=y iff b^y = x$
${log}_{7} y = - 6$ $log_7 y = -6$

How do you write 7^-6=y7−6=y7^-6=y in logarithmic form?