How do you write $9x=2y+13$ in slope intercept form?

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Answer 1 · 2016-10-01T03:28:18

Slope intercept form is $y = mx + b$ .

$9x - 13 = 2y$

$y = 9/2x - 13/2$

Hopefully this helps!

Answer 2 · 2016-10-01T03:56:08

$y=9/2x-13/2$

The slope-intercept form for a linear equation is $y=mx+b$ , where $m$ is the slope and $b$ is the y-intercept.

In order to write the equation $9x=2y+13$ in slope-intercept form, solve for $y$ .

$9x=2y+13$

Subtract $2y$ from both sides.

$-2y+9x=13$

Subtract $9x$ from both sides.

$-2y=-9x+13$

Divide both sides by $-2$ .

$y=(-9x)/(-2)+13/(-2)$

Simplify.

$y=9/2x-13/2$

$m=9/2$
$b=-13/2$

graph{y=9/2x-13/2 [-10.85, 9.15, -8.19, 1.81]}

How do you write 9x=2y+139x=2y+13 in slope intercept form?