How do you write a function rule for x = 2, 4, 6 and y = 1, 0, -1?

1 Answer
Mar 20, 2018

y=f(x) = -1/2x+2

Explanation:

Set the i^("th") point as: P_i->(x_i,y_i)

Change in x sequence is 2
Change in y sequence is -1

Gradient (slope) ->m=("change in "y)/("change in " x) =-1/2

Assuming there is a direct link between x and y numbers of sequence we have:

P_1->(x_1,y_1)=(2,1)
P_2->(x_2,y_2)=(4,0)
P_3->(x_3,y_3)->(6 ,-1 )

Relating m to, say, point 2 we have:

m=-1/2=(y-y_2)/(x-x_2)=(y-0)/(x-4)

-1/2= (y-0)/(x-4)

Multiply both sides by (+2)

-1=(2(y-0))/(x-4)

Multiply both sides by (x-4)

-(x-4)=2y

-x+4=2y

y=-1/2x+2
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The question is specific in that it states 'function rule for x'

So we write it as: y=f(x) = -1/2x+2

Tony B