How do you write a line through: (4-2), parallel to y=x+2?

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Answer 1 · 2018-04-11T01:45:28

Equation of parallel line through (4,-2) is

$color(maroon)(y = x - 6$

Standard form of slope-intercept equation is

$y = mx + c, " where m is the slope and c the y-intercept"$

Given equation is #y = x + 2"

Hence $Slope = m = 1$

$"Parallel line will also have the same slope m = 1"$

Having known slope and a point on the line, Equation for the same is

$(y - y_1 = m * (x - x_1)$

$y + 2 = 1 * (x - 4)$

$color(maroon)(y = x - 4 - 2 = x - 6$

Answer 2 · 2018-04-11T01:45:36

$y=x-6$

Parallel lines have the same slope (in this case, the slope is 1).

Slope-intercept form of a line: $y=mx+b$ where $m$ represents slope and $b$ the y-intercept

$y=x+b rarr$ This is our current equation (we don't know the y-intercept).

Let's plug in the point given to us: $(4, -2)$

$-2=4+b$

$b=-6 rarr$ This is the y-intercept

Our equation is $y=x-6$