How do you write a line through: (4-2), parallel to y=x+2?
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Equation of parallel line through (4,-2) is
#color(maroon)(y = x - 6#
Standard form of slope-intercept equation is
#y = mx + c, " where m is the slope and c the y-intercept"#
Given equation is #y = x + 2"
Hence #Slope = m = 1#
#"Parallel line will also have the same slope m = 1"#
Having known slope and a point on the line, Equation for the same is
#(y - y_1 = m * (x - x_1)#
#y + 2 = 1 * (x - 4)#
#color(maroon)(y = x - 4 - 2 = x - 6#
Parallel lines have the same slope (in this case, the slope is 1).
Slope-intercept form of a line: #y=mx+b# where #m# represents slope and #b# the y-intercept
#y=x+b rarr# This is our current equation (we don't know the y-intercept).
Let's plug in the point given to us: #(4, -2)#
#-2=4+b#
#b=-6 rarr# This is the y-intercept
Our equation is #y=x-6#