How do you write an equation for the line parallel to #y=-8x-6# that contains P(2,7)?
1 Answer
May 24, 2015
y1 = -8x - 6
Equation of Line y2 parallel to y1:
y2 = -8x + b .
Find b by writing that Line y2 passing at point (2, 7)
7 = -8(2) + b = -16 + b -> b = 7 + 16 = 23
y2 = -8x + 23.
