How do you write an equation in point slope form parallel to -2x-3y = -2 and passing through (2, -2)?

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Answer 1 · 2016-02-22T22:11:17

Since the lines are parallel, this means that their slope is equal.

#-2x - 3y = -2#

#-3y = -2 + 2x#

#y = 2/3 - 2/3x#

The slope is #-2/3#

We can now use the point and the slope to the find the equation of the line by plugging our values into point slope form.

#y - y_1 = m(x - x_1)#

#y - (-2) = -2/3(x - 2)#

#y + 2 = -2/3x + 4/3#

#y = -2/3x - 2/3#

Hopefully this helps!