How do you write an equation in slope-intercept form for a line parallel to y = -5 that passes through the point (-1,-8)?

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How do you write an equation in slope-intercept form for a line parallel to y = -5 that passes through the point (-1,-8)?

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Answer 1 · 2017-04-13T05:28:01

$y = - 8$ $y = -8$

Explanation:

Slope intercept form is $y = m x + b$ $y = mx + b$ where $m$ $m$ = slope, and $b = y$ $b = y$ intercept $(0, b)$ $(0, b)$ .

When a line is in the form $y = - 5$ $y = -5$ , it has $m = 0$ $m = 0$ , therefore the line is a horizontal line. Horizontal lines have different values of $x$ $x$ , but the same $y$ $y$ -value. The line passes through points such as $(- 1, - 5), (0, - 5), (2, - 5), (4, - 5)$ $(-1, -5), (0, -5), (2, -5), (4, -5)$ .

A line that is parallel has the same slope: $m = 0$ $m = 0$ . It is also a horizontal line. To pass through $(- 1, - 8)$ $(-1, -8)$ the line must be $y = - 8$ $y = -8$

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How do you write an equation in slope-intercept form for a line parallel to y = -5 that passes through the point (-1,-8)?

1 Answer

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