How do you write an equation in slope intercept form given 5x+8y=96?

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Answer 1 · 2016-07-14T19:22:44

$y = - \frac{5}{8} x + 12$ $y = -5/8x + 12$

Slope intercept form: $y = m x + b$ $y=mx+b$ where $m$ $m$ is the slope and $b$ $b$ is the y intercept.

$5 x + 8 y = 96$ $5x + 8y = 96$

Let's rewrite this equation in slope intercept form. First get the $y$ $y$ variable term by itself.

$8 y = 96 - 5 x$ $8y = 96 - 5x$

Now divide out the $8$ $8$ .

$y = 12 - \frac{5}{8} x$ $y = 12 - 5/8x$

Rearrange the terms on the right side of the equal sign to match the slope intercept equation from above.

$y = - \frac{5}{8} x + 12$ $y = -5/8x + 12$

If you were to graph this line it would look like: graph{-5/8x + 12 [-10.04, 9.96, 7.46, 17.88]}