Question

How do you write an equation in slope intercept form given that the line passes through the point (-2, -5) and has a slope of -3?

Answer 1

The main formula of a line is;
`y=ax+b`

We should use one point to find the real equation. If we use (-2,-5) point;
`y= ax+b => -5=-2a+b`;
a is the slope of the equation, we found that as `-3`;
`-5=(-2*-3) + b => -5=6 +b => b=-11`;
So the equation of the line will be;
`y=ax+b => ul (y= -3x-11)`