Question

How do you write an equation in slope intercept form given that the line passes through the point (−6, 4) and has a slope of 4/3?

Answer 1

The main formula of a line is;
`y=ax+b`

We should use one point to find the real equation. If we use (-6,4) point;
`y= ax+b => 4=-6a+b`;
a is the slope of the equation, we found that as `4/3`;
`4=(-6*4/3) + b => 4=-8 +b => b=12`;
So the equation of the line will be;
`y=ax+b => ul (y= 4/3x+12)`