How do you write an equation of a line given point (4, -1) and perpendicular to a line with equation 3x + y =4?

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Answer 1 · 2016-05-14T15:14:08

#y = 4 - 3x -># the slope of this line is -3

The slope of a perpendicular line is the negative reciprocal , therefore #1/3#.

Now, using point slope form, #y - y_1 = m(x - x_1)#, we get:

#y - (-1) = 1/3(x - 4)#

#y + 1 = 1/3x - 4/3#

#y = 1/3x -7/3#

Hopefully this helps!