How do you write an equation of a line given slope 5/2 and passes through (4,-1)?

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Answer 1 · 2016-02-18T17:17:08

$y = \frac{5}{2} x - 11$ $y = 5/2x - 11$

To determine the equation of the line we can use the point slope formula and plug in the values given in the question.

$(y - y_{1}) = m (x - x_{1})$ $(y - y_1) = m(x - x_1)$

$m = \frac{5}{2}$ $m = 5/2$
$x_{1} = 4$ $x_1 = 4$
$y_{1} = - 1$ $y_1=-1$

$(y - (- 1)) = \frac{5}{2}$ $(y - (-1)) = 5/2$ (x - 4)#

$y + 1 = \frac{5}{2} x - 10$ $y +1 = 5/2x - 10$

$y + 1 - 1 = \frac{5}{2} x - 10 - 1$ $y +1-1 = 5/2x - 10-1$

$y = \frac{5}{2} x - 11$ $y = 5/2x - 11$