How do you write an equation of a line passing through (2, -2), perpendicular to #y = –x + 3#?
1 Answer
Dec 6, 2017
Explanation:
#"given a line with slope m then the slope of a line"#
#"perpendicular to it is"#
#•color(white)(x)m_(color(red)"perpendicular")=-1/m#
#"the equation of a line in "color(blue)"slope-intercept form"# is.
#•color(white)(x)y=mx+b#
#"where m is the slope and b the y-intercept"#
#y=-x+3" is in this form"#
#"with "m=-1#
#rArrm_(color(red)"perpendicular")=-1/(-1)=1#
#rArry=x+blarrcolor(blue)"is the partial equation"#
#"to find b substitute "(2,-2)" into the partial equation"#
#-2=2+brArrb=-4#
#rArry=x-4larrcolor(red)"in slope-intercept form"#