How do you write an equation of a line passing through (3, -4), perpendicular to # 3y=x-2#?

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Answer 1 · 2016-10-04T19:00:00

#"equation of line passing through (3,-4) is "y=-3x+5#

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#color(blue)(3y=x-2)#

#color(blue)(y=1/3x-2/3)#

#"the slope of blue line is : "m_"blue"=1/3#

#m_"red":"the slope of red line"#

#"so " alpha=90 " , " m_"blue" * m_"red"=-1#

#1/3* m_"red"=-1#

#m_"red"=-3#

#y-y_1=m_"red" *(x-x_1)#

#y+4=-3(x-3)#

#y+4=-3x+9#

#y=-3x+9-4#

#y=-3x+5#