How do you write an equation of a line with (-11,1), (-9,-3)?

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Answer 1 · 2016-03-05T10:59:35

#2x+y+21=0#

The equation of a line joining points #(x_1,y_1)# and #(x_2,y_2)# is given as

#(y-y_1)=((y_2-y_1)/(x_2-x_1))(x-x_1)#.

Hence equation of a lie joining #(-11,1)# and #(-9,-3)# is given by

#(y-1)=(((-3)-1)/((-9)-(-11)))(x-(-11))# or

#(y-1)=((-4)/(-9+11))(x+11)# or

#(y-1)=((-4)/2)(x+11)# or #(y-1)=(-2)(x+11)# or

#y-1=-2x-22# or #2x+y+21=0#