How do you write an equation of a line with slope 1 and y-intercept 1?

2 Answers
Nov 20, 2016

y=x+1y=x+1

Explanation:

Equation of a line with slope mm and yy-intercept cc is

y=mx+cy=mx+c

and hence equation of a line with slope 11 and yy-intercept as 11 is

y=1xxx+1y=1×x+1 or y=x+1y=x+1
graph{y=x+1 [-5.938, 4.06, -2.12, 2.88]}

Nov 20, 2016

y=x+1y=x+1

Explanation:

The equation of a line in color(blue)"slope-intercept form"slope-intercept form is.

color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))
where m represents the slope and b, the y-intercept.

Here m = 1 and b = 1

rArry=x+1" is the equation of the line"