How do you write an equation of slope-intercept form for the line with a x-intercept of 1/3 and a y intercept of -1/4?

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Answer 1 · 2016-06-10T09:50:23

#y=3/4x-1/4#,

where #3/4# is slope of line and #-1/4# is intercept on #y#-axis.

Equation of a line in slope intercept form is #y=mx+c#, where #m# is the slope of the line and #c# is its intercept on #y#-axis.

Equation of line whose #x#-intercept is #a# and #y#-intercept is #b# is

#x/a+y/b=1#

As here, #x#-intercept is #1/3# and #y#-intercept is #-1/4#, the equation is

#x/(1/3)+y/(-1/4)=1# or

#3x-4y=1# or

#4y=3x-1# or #y=3/4x-1/4#, where #3/4# is slope of line and #-1/4# is intercept on #y#-axis.