Question

How do you write `b^- (4/7)` in radical form?

Answer 1

`b^(-(4/7))=color(red)(1/(root(7)(b^4))`

Explanation:

General observations on exponents:
`color(white)("XXX")p^(-q)=1/(p^q)`

`color(white)("XXX")p^(r/s)=(p^r)^(1/s)=root(s)(p^r)`

Base on the above, we have
`color(white)("XXX")b(-4/7)=1/(b^(4/7))=1/(root(7)(b^4))`