Question

How do you write `e^(1/2)=1.6487` in logarithmic form?

Answer 1

`e^(1/2)=1.6487 iff ln1.6487=1/2, or, 0.5.`

Explanation:

Recall that, `e^x=y iff lny=x.`

`:. e^(1/2)=1.6487 iff ln1.6487=1/2, or, 0.5.`