How do you write in simplest radical form the coordinates of point A if A is on the terminal side of angle in standard position whose degree measure is $θ$ $theta$ : $O A = 2$ $OA=2$ , $θ = - 60^{\circ}$ $theta=-60^circ$ ?

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Answer 1 · 2018-02-28T10:20:09

$(1, - \sqrt{3})$ $color(blue)((1,-sqrt(3))$

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Using the sine and cosine functions, the x coordinate is given by:

$x = 2 cos (- 60^{\circ})$ $x=2cos(-60^@)$

and the y coordinate is given by:

$y = 2 sin (- 60^{\circ})$ $y=2sin(-60^@)$

$:.$

$x=2sin(-60^@)=2*1/2=1$

$y=2sin(-60^@)=2*-sqrt(3)/2=-sqrt(3)$

$sqrt(3)$ is in its simplest form. So coordinates of point $bb(P)$ are:

$color(blue)((1,-sqrt(3))$

How do you write in simplest radical form the coordinates of point A if A is on the terminal side of angle in standard position whose degree measure is thetaθtheta: OA=2OA=2OA=2, theta=-60^circθ=−60∘theta=-60^circ?