How do you write in simplest radical form the coordinates of point A if A is on the terminal side of angle in standard position whose degree measure is $θ$ $theta$ : OA=9, $θ = 150^{\circ}$ $theta=150^circ$ ?

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How do you write in simplest radical form the coordinates of point A if A is on the terminal side of angle in standard position whose degree measure is $θ$ $theta$ : OA=9, $θ = 150^{\circ}$ $theta=150^circ$ ?

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Answer 1 · 2018-03-04T07:31:23

Coordinates of $A (- \frac{9 \sqrt{3}}{2}, \frac{9}{2})$ $A (-(9sqrt3)/2, 9/2)$

Explanation:

$¯ ¯¯¯¯ ¯ O A = 9, θ = 150^{\circ}$ $bar(OA) = 9, theta = 150^@$

A is in second quadrant.

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To find coordinates of A.

$A_{x} = ¯ ¯¯¯¯ ¯ O A cos θ = 9 \cdot cos 150 = 9 \cdot - cos 30 = - 9 \cdot (\frac{\sqrt{3}}{2}) = - \frac{9 \sqrt{3}}{2}$ $A_x = bar(OA) cos theta = 9 * cos 150 = 9 * - cos 30 = - 9 * (sqrt3 / 2) = -(9 sqrt3)/2$

$A_{y} = ¯ ¯¯¯¯ ¯ O A sin θ = 9 \cdot sin 150 = 9 \cdot sin 30 = 9 \cdot (\frac{1}{2}) = \frac{9}{2}$ $A_y = bar(OA) sin theta = 9 * sin 150 = 9 * sin 30 = 9 * (1/2) = 9/2$

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How do you write in simplest radical form the coordinates of point A if A is on the terminal side of angle in standard position whose degree measure is $θ$ $theta$ : OA=9, $θ = 150^{\circ}$ $theta=150^circ$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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How do you write in simplest radical form the coordinates of point A if A is on the terminal side of angle in standard position whose degree measure is θtheta: OA=9, θ=150∘theta=150^circ?

1 Answer

Explanation:

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How do you write in simplest radical form the coordinates of point A if A is on the terminal side of angle in standard position whose degree measure is $θ$ $theta$ : OA=9, $θ = 150^{\circ}$ $theta=150^circ$ ?