How do you write ${log}_{2} y = 5$ $log_2 y=5$ in exponential form?

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Answer 1 · 2016-08-02T03:37:44

${log}_{a} (b) = c \to a^{c} = b$ $log_a(b) = c -> a^c = b$

${log}_{2} (y) = 5 \to 2^{5} = y \Rightarrow y = 32$ $log_2(y) = 5 -> 2^5 = y => y = 32$

If you want it purely in exponential form, you can say:

$2^{5} = y$ $2^5 = y$ or $2^{5} = 32$ $2^5 = 32$ .

Hopefully this helps!

How do you write log2y=5log_2 y=5 in exponential form?