How do you write #log_5(625)=x # in exponential form?

Question

12097 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-06-18T21:49:08

#5^x=625#
#x=4#

The definition of a logarithm says :

#log_bx=y iff b^y=x#

In other words you can say that logarithm is the exponent to which you must raise the base #(b)# to get number #x#.

In this case #x# is the exponent to which you have to raise base (5) to get 625

#5^x=625#
This is the exponential form.

To find the answer you have to count which power of 5 is 625

#5^1=5#
#5^2=5*5=25#
#5^3=25*5=125#
#5^4=125*5=625#

#5^4=625# so #x=4#