How do you write out the formula, complete ionic, and net ionic reaction for a reaction occurring when lead(IV) nitrate reacts with barium chromate?

Question

How do you write out the formula, complete ionic, and net ionic reaction for a reaction occurring when lead(IV) nitrate reacts with barium chromate?

1 Answer

Impact of this question

1590 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-22T16:41:48

$2 B a C r O_{4} (a q) + P b {(N O_{3})}_{4} (a q) \to P b {(C r O_{4})}_{2} (s) ⏐ ↓ + 2 B a {(N O_{3})}_{2} (a q)$ $2BaCrO_4(aq) + Pb(NO_3)_4(aq) rarr Pb(CrO_4)_2(s)darr + 2Ba(NO_3)_2(aq)$

Explanation:

I have an idea that barium chromate is pretty insoluble stuff. Nevertheless, lead(IV)chromate is probably even more insoluble.

The net ionic equation is:

$P b^{4 +} + 2 C r O_{4}^{2 -} \to P b {(C r O_{4})}_{2} (s) ⏐ ⏐ ↓$ $Pb^(4+) + 2CrO_4^(2-)rarr Pb(CrO_4)_2(s)darr$

The nitrate and the barium ions are along for the ride. I leave it to you to write the formula equation.

Science

Math

Humanities

... and beyond

How do you write out the formula, complete ionic, and net ionic reaction for a reaction occurring when lead(IV) nitrate reacts with barium chromate?

1 Answer

Explanation:

Related questions

Impact of this question