How do you write #sqrt(242)# in simplified radical form? Algebra Radicals and Geometry Connections Simplification of Radical Expressions 1 Answer Daniel L. Oct 21, 2015 It can be written as #11sqrt(2)# Explanation: If you try to write #242# as a product of prime factors you will find, that #242=2*11*11#, so #sqrt(242)=sqrt(2*11*11)=sqrt(2)*sqrt(11*11)=11sqrt(2)# Answer link Related questions How do you simplify radical expressions? How do you simplify radical expressions with fractions? How do you simplify radical expressions with variables? What are radical expressions? How do you simplify #root{3}{-125}#? How do you write # ""^4sqrt(zw)# as a rational exponent? How do you simplify # ""^5sqrt(96)# How do you write # ""^9sqrt(y^3)# as a rational exponent? How do you simplify #sqrt(75a^12b^3c^5)#? How do you simplify #sqrt(50)-sqrt(2)#? See all questions in Simplification of Radical Expressions Impact of this question 8327 views around the world You can reuse this answer Creative Commons License