How do you write the augmented matrix for the system of linear equations $4 x - 3 y = - 5, - x + 3 y = 12$ $4x-3y=-5, -x+3y=12$ ?

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Answer 1 · 2017-08-08T09:19:00

The solution is $((x),(y))=((28/3),(43/9))$

We perform the Gauss Jordan elimination with the augmented matrix

$M=((4,-3,:,-5),(-1,3,:,12))$

We perform the row operations

$R2larr4R2+R1$ , $=>$ , $((4,-3,:,-5),(0,9,:,43))$

$R2larr(R2)/9$ , $=>$ , $((4,-3,:,-5),(0,1,:,43/9))$

$R1larrR1+3R2$ , $=>$ , $((4,0,:,28/3),(0,1,:,43/9))$

$R1larr(R1)/4$ , $=>$ , $((1,0,:,28/12),(0,1,:,43/9))$

How do you write the augmented matrix for the system of linear equations 4x-3y=-5, -x+3y=124x−3y=−5,−x+3y=124x-3y=-5, -x+3y=12?